Analytically solving ODEs with non-constant coefficients for a specific t

thesteve
Messages
1
Reaction score
0
Given an ODE in the form of f(t)y''+g(t)y'+h(t)y=0

If all I am looking for is the y(t) at a specific value of t and NOT the general solution, can I just plug in that value of t into the original ODE and then solve it analytically or is a numeric solution the only way?
 
Last edited:
Physics news on Phys.org
Plugging in a value of t would be a very coarse approximation near that value of t. Not guaranteed to be accurate. The only way you might get away with it is if you had some kind of error bounds.

Plus, you might have an initial condition that is far away from that value of t. In that case, it's likely to be way off.

Differential equations are basically just vector fields (time-varying vector fields, in this case). A solution to a differential equation is obtained by just going where the arrows point. With that intuition in mind, it should be clear what is wrong with your proposed method. If you are following the arrows as they vary in time, there's no reason that picking some point in time will work over long periods of time. The vector field may be completely different at another point in time, so it will take you in a very different direction.

I think maybe the method of integrating factors might work here.
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top