Angle Between Two Vectors & Components Calculation

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To determine the angle between two vectors, the dot product formula A "dot" B = |A|*|B|*cos(angle) is used, where the angle is derived from the relationship between the vectors. The component of a vector along the direction of another vector, such as i+j, is found by taking the dot product of the vector with the unit vector of i+j. Perpendicular components refer to vectors that intersect at a 90-degree angle, while "along" indicates parallel vectors with an angle of zero. The discussion emphasizes the importance of understanding these concepts for solving vector problems effectively. Clarity on these definitions and calculations is essential for successful vector analysis.
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Homework Statement


1. How can i determine the angle between two vectors
2. The Component of vector ( a vector, given below ) along the direction of i+j
3. Let there be a vector and b vector , then find component the component of a vector along perpendicular direction of b vector.

Please also do tell me what do you mean by along the direction and perpendicular to some vector and projection.


Homework Equations


a vector=2i + 3j + 4k
b vector = 3i + 4j + 5k


The Attempt at a Solution


Not Attempted yet because didn't understand it's meaning.
 
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Perpendicular (orthogonal) means that the vectors are at a 90 degree angle or pi/2 radians with each other.

Along, would mean they are parallel (angle between = 0)

As for the formulas:

A "dot" B = |A|*|B|*sin(angle between them) = AxBx + AyBy + AzBz

A "cross" B = A x B = |A|*|B|*sin(angle between them) = det( [i,j,k ; Ax,Ay,Az ; Bx,By Bz] )
 
iamthegelo said:
Perpendicular (orthogonal) means that the vectors are at a 90 degree angle or pi/2 radians with each other.

Along, would mean they are parallel (angle between = 0)

As for the formulas:

A "dot" B = |A|*|B|*sin(angle between them) = AxBx + AyBy + AzBz

A "cross" B = A x B = |A|*|B|*sin(angle between them) = det( [i,j,k ; Ax,Ay,Az ; Bx,By Bz] )

My physics teacher told me the formula is : A "dot" B = |A|*|B|*cos(angle between them) ( not sin )
 
dhruv_arora said:
My physics teacher told me the formula is : A "dot" B = |A|*|B|*cos(angle between them) ( not sin )
It is right. Since you know this formula why can't you find the angle between the vectors?
 
i founded it.
but i can't get what it means by " Find The component of Avec along the direction of i+j "
 
dhruv_arora said:
My physics teacher told me the formula is : A "dot" B = |A|*|B|*cos(angle between them) ( not sin )

Oops, I remember changing that mistake, but yeah it is cosine.

A projection along i+j is the dot product of

Vector1 and Unit vector of i+j, it is the component of vector1 along the vector i+j.
 
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