Angle of the shaft and Mohr's Circle question

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SUMMARY

The discussion focuses on calculating the angle between the maximum principal stress and the shaft axis for a shaft with a diameter of 0.2m, subjected to a torque of 150 KNm and a compressive axial thrust of 520KN. The participant successfully determined the shear stress as 95.5 MPa, the direct stress as -16.55 MPa, and the principal stresses as σ1=87.21 MPa and σ2=-103.765 MPa. Additionally, the participant aimed to draw Mohr's Circle to validate these results.

PREREQUISITES
  • Understanding of shear and direct stress calculations
  • Familiarity with principal stress concepts
  • Knowledge of Mohr's Circle for stress analysis
  • Basic mechanics of materials principles
NEXT STEPS
  • Study the derivation of principal stresses in solid mechanics
  • Learn how to construct Mohr's Circle for two-dimensional stress states
  • Explore the effects of torque on shear stress in cylindrical shafts
  • Review axial loading and its impact on stress distribution
USEFUL FOR

Mechanical engineers, students studying solid mechanics, and professionals involved in stress analysis of rotating shafts will benefit from this discussion.

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Homework Statement


Shaft diameter: 0.2m, Torque: 150 KNm, Axial Thrust(compressive): 520KN

Trying to find the angle between maximum principal stress and shaft axis and then to draw the mohr's circle to confirm this results


Homework Equations






The Attempt at a Solution


I calcualted the:
shear stress: 95.5 *10^6
direct stress: -16.55*10^6
Principal Stresses: σ1=87.21*10^6, σ2= -103,765


Any help will appreciated.
 
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