Angle of the slope when the object start moving

  • Thread starter Thread starter goldfish9776
  • Start date Start date
  • Tags Tags
    Angle Slope
AI Thread Summary
When an object starts moving down a slope, the angle of the slope, theta, is larger than the angle at which it begins to move, theta(s), due to the difference in friction types. Static friction (Fs) is greater than kinetic friction (Fk), meaning that once the object starts sliding, it can continue to do so at a lower angle. The relationship between the angles and friction coefficients indicates that sliding can occur at angles slightly below the static friction threshold. The discussion clarifies that while an object can slide at angles less than theta(s), it will not start moving until the angle exceeds theta(s). Overall, the key point is that the angle of movement is influenced by the transition from static to kinetic friction.
goldfish9776
Messages
310
Reaction score
1

Homework Statement


when the object is moving , why the theta is larger than the theta(s) when the object is started moving ?
I was told that when the object is moving , the Fk will become smaller than Fs , right ? so, IMO , the theta should be larger than the theta(s) , am i right ?

Homework Equations

The Attempt at a Solution


tan(theta k)= Fk / N = = μ k (N) / N
tan (theta s) =Fs / N = μ s (N ) / N
angle is directly proportional to μ k and μ s
 

Attachments

  • DSC_0176.JPG
    DSC_0176.JPG
    45.5 KB · Views: 396
Physics news on Phys.org
goldfish9776 said:
when the object is moving , why the theta is larger than the theta(s) when the object is started moving ?
They could have written >=, but the exact border case rarely has physical relevance - no slope is perfectly flat and so on.
goldfish9776 said:
I was told that when the object is moving , the Fk will become smaller than Fs , right ?
Sliding friction is usually smaller than static friction. Once the object starts moving, you can reduce the tilt angle and the object will continue sliding.
 
mfb said:
They could have written >=, but the exact border case rarely has physical relevance - no slope is perfectly flat and so on.
Sliding friction is usually smaller than static friction. Once the object starts moving, you can reduce the tilt angle and the object will continue sliding.
do u mean when the object is sliding , no matter the angle is larger than μ s or the angle is slightly smaller than μ s , the object will still sliding down the plane ?
 
μ s is not an angle.

There is an angle ##\theta_0## where the object starts sliding (it starts sliding for all angles larger than that, and does not start for all angles smaller than that). There is a different angle ##\theta_1 < \theta_0##, between those two angles an object that is sliding keeps sliding (forever), but won't start sliding on its own if it is at rest.
 
mfb said:
θ1<θ0
as you stated , why the book gave θ(when it's moving ) will bigger than θ(when it's about to move ) ?
 
The logic is in the other direction: if the angle is larger, it is certainly moving.
 
  • Like
Likes goldfish9776
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top