Angular Acceleration Calculation: Solving Problems with Formulas | Get Help Now

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The discussion centers on calculating angular acceleration and related parameters for a wheel with a given initial velocity and applied force. The user successfully determined the angular acceleration as 2.22 rad/s² and calculated the radius of the wheel to be 1.56 m based on the rotational inertia and applied force. However, they are uncertain about how to calculate the time it takes to stop the wheel with a constant torque and need assistance with determining the force applied and the mass of the wheel. The user has made some progress in calculating angular displacement but acknowledges that their answers may not fully incorporate torque or radius. Additional input from others is sought to clarify these calculations and ensure accuracy.
ProSk8ter474
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Heres the problem. I'm trying to solve it at the moment, and I'll be posting what I have done so far. I'm very short on formulas for this so I will need help. Thanks a lot.

1) a) Determine angular acceleration of a wheel, which has a velocity of 200 rad/min after rotating for 1.5s from start.
b) If the wheel has a rotational inertia of 5500 kgm2(squared), what would be its radius if 5000 N of forced had been applied?
c) If the same wheel, having reached a final velocity of 200 rad/min, were slowed down with a constant torque of 10,000 NM applied (with same radius), how long would it take to stop the wheel?
d.) How much force was applied?
e.) Determine the mass of the wheel. (the wheel is a solid disk)

Again, your help would be greatly appreciated.
 
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Ok, here's what I'm thinking.

a.) (200/60)rad/min = (10/3)rad/s
Angular Acceleration = (dW/dT)
(3.33rad/s)/(1.5s) = 2.22 rad/s^2

b.) I = MR^2 F = Ma
5000N = (M)(2.22rad/s^2)
M = 2252.25 kgm/rad

I = MR^2
(5500kgm^2) = (2252.25kgm/rad)(R^2)
R = 1.56 m/rad

c.) No idea. Please Help
d.) No idea. Please Help
e.) No idea. Please Help
 
Possibility for Part C

Angular Displacement = (W^2-Wo^2)/(2*Angular Acceleration)
= (11.11rad^2/s^2)/(4.44rad/s^2)
= 2.5 rad
Angular Displacement = (t/2)(Wo+W)
=(2.5 rad) = (t/2)*(10/3rad/s)
=(2.5 rad)/(3.33rad/s)
= .75s = (t/2)
t = 1.5 s

Now, I think I solved that part, but I didn't end up using Torque or the Radius, so my answer could be wrong. Please reply with any comments
 
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