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## Main Question or Discussion Point

Consider a massless string going over a massless frictionless pulley with masses M1 and M2 at the end of the string.

The tension in the string would be same.

The torque equation of the pulley says (T1-T2)=Iα .Now L.H.S is zero since T1=T2 and also I=0 .

So,we have a condition 0=(0)(α) which makes α indeterminate .But we know that the pulley rotates with some angular acceleration.

So ,how is α determined ?

Is α=a/R where R is the radius of the pulley and a=[(M2-M1)g]/(M1+M2) ?

The tension in the string would be same.

The torque equation of the pulley says (T1-T2)=Iα .Now L.H.S is zero since T1=T2 and also I=0 .

So,we have a condition 0=(0)(α) which makes α indeterminate .But we know that the pulley rotates with some angular acceleration.

So ,how is α determined ?

Is α=a/R where R is the radius of the pulley and a=[(M2-M1)g]/(M1+M2) ?