Angular Acceleration of a washer (1 Viewer)

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ryan838

I dont really know what to do on this problem. So if someone could get me pointed in the right direction I would appreciate it.

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 7.0 rev/s in 13.0 s. At this point the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub slows to rest in 14.0 s. Through how many revolutions does the tub turn during this 27 s interval? Assume constant angular acceleration while it is starting and stopping.

Doc Al

Mentor
You have to apply the kinematic equations for constant acceleration:
x = x0 + v0t + 1/2 a t2
vf2 = vi2 + 2a&Delta;x

Of course, instead of distance, velocity, and acceleration, you must use angular displacement, angular velocity, and angular acceleration. Make sense?

ryan838

No that doesnt really make to much sense. Here is what I did so maybe you can tell me where I went wrong.

I took the 7 rev/s and divided it by 13s to get the acceleration to be .54 rev/s. Then to get the deacceleration I took 7 rev/s divided by 14s to get -.5 rev/s. So for the first 13s it is speeding up by .54 rev/s right? Then the last 14s it is deacclerating at a rate of -.5 rev/s? From there I dont get how to put it into the equation you posted. Thanks for your help though.

Doc Al

Mentor
Originally posted by ryan838
I took the 7 rev/s and divided it by 13s to get the acceleration to be .54 rev/s.
Right. The units should be rev/s2. (I should have given you the equation &Delta;v = at .)
Then to get the deacceleration I took 7 rev/s divided by 14s to get -.5 rev/s.
So for the first 13s it is speeding up by .54 rev/s right? Then the last 14s it is deacclerating at a rate of -.5 rev/s? From there I dont get how to put it into the equation you posted.
You know the times and the accelerations. Now you need to find the angle (distance in revs). Which of the two equations I gave give the distance? (The other one you don't need!)

ryan838

Thank you for your help. I got the right answer which turned out to be 94.63 revolutions.

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