I Angular Momentum Hydrogen Atom Problem: Physically Explained When L=0

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In quantum mechanics hydrogen atom problem ##L=\sqrt{l(l+1)}\hbar##. What that means physically when ##L=0##?
 
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L = 0 is only possible when l = 0 which means that the wave function has no angular dependence and spherically symmetric.
 
And also for a particle moving in some potential energy other than the hydrogenic ##V\propto 1/r##, the energy eigenfunctions with ##L=0## are spherically symmetric. These systems include the 3D harmonic oscillator ##V(x,y,z) = C(x^2 + y^2 + z^2 )## and the spherical potential well where ##V(r) = 0## if ##r<R## and ##V(r) = V_0## when ##r\geq R##.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
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