Animal Foraging Radius Equation Part 2

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The discussion focuses on calculating an animal's foraging radius using a specific equation and provided parameters. The user seeks clarification on their calculations and expresses concern about potential typos in the formula. A key point raised is the importance of consistent units throughout the calculations, as discrepancies could lead to incorrect results. Additionally, suggestions are made to simplify the equation by grouping terms to reduce arithmetic errors. The overall emphasis is on ensuring that the final result reflects a proper distance measurement.
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Homework Statement



I asked a similar question before relating to an animal's foraging radius. I think there was a typo but I'd like to show another example to see if I'm on the right track.

The parameter values are as follows:

Q= 5.2 × 106 J
C = 1.5kg
d= 0.055kg per hour
k= 2.0 Joules/m
Ema = 24 Watts
Emc = 42 Watts
T = 48 hours
v= 45km per hour
t= 12 hours


Homework Equations



r = [QC +Qdt - T(Ema+Emc/2)/(2k+ (2Qd/v))]


The Attempt at a Solution



(7800000 + 5.2*10^6*.055*12 - 172800 (45))/16.711111111111112
 
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killbot2000 said:

Homework Statement



I asked a similar question before relating to an animal's foraging radius. I think there was a typo but I'd like to show another example to see if I'm on the right track.

The parameter values are as follows:

Q= 5.2 × 106 J
C = 1.5kg
d= 0.055kg per hour
k= 2.0 Joules/m
Ema = 24 Watts
Emc = 42 Watts
T = 48 hours
v= 45km per hour
t= 12 hours


Homework Equations



r = [QC +Qdt - T(Ema+Emc/2)/(2k+ (2Qd/v))]


The Attempt at a Solution



(7800000 + 5.2*10^6*.055*12 - 172800 (45))/16.711111111111112


A minor point is that it would be good practice to group the first two numerator terms as
Q(C + DT). One less arithmetical operation to do and error risked. Similarly you could take out the factor 2 in the denominator

More important is you must pay constant attention to units. E.g.you do not give a unit for your result - metres or Km...

It seems there is something wrong about your physical units, maybe misquotation of formulae or units? The expression I just gave is JoulesXKg. The way you have written the equation they appear as such in the result which is nonsense - you must get a distance. The denominator has a similar anomaly and you would be adding things of incompatible dimensions - it is probably the second term that is wrong.
 
(I see I drew attention to the same units and dimensions issue in your previous thread.)
 
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