# Another 2 dimensional problem

1. Jun 2, 2006

### rcwha

another 2 dimensional problem :(

The best leaper in the animal kingdom is the puma, which can jump to a height of 11.5ft (3.51m) when leaving the ground at an angle of 43 degress. With what speed, must the animal leave the ground to reach that height?

at first i thought i could find the time it took for the puma to get to it's maximum height by setting V=0 but i dont that's right...

i tried using the equation

change in y=(sin43)Vot-.5g(t^2)

with change in y = 3.51 m

but i dont know how to solve for t or Vo

this question would be so much easier if the question gave the horizontal distance but it doesnt..so what do i do?

2. Jun 2, 2006

### Hootenanny

Staff Emeritus
You need a kinematic equation with inital velocity, final velocity, acceleration and displacement. Can you think of one?

HINT: You know the final velocity

~H

3. Jun 2, 2006

### rcwha

is it V^2=Vyo^2 + 2ay

a= -9.8
im assuming final velocity= 0 b/c that's what v is going to = at its max height

thank you...i ended up with the right answer

4. Jun 2, 2006

### Hootenanny

Staff Emeritus
Spot on. No problem

~H