- #1
Redoctober
- 48
- 1
Homework Statement
∫(sin(x-2))^(1/3)
The Attempt at a Solution
I reached until -∫1/((1-u^2)^1/3).du where u = sin(x)
Then i got stuck as i tried to integrate to inverse function but it doesn't work as that is for ∫1/((a-x^2)^1/2)
another try was to separate the sin(x-2)
where i reached until
∫(1-(cos(x-2))^2)*(sin(x-2))^(5/3).dx
then using u= cos(x-2) u get -du=sin(x-2) . but this doesn't work too -.- !
Help