(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Another NMOS-transistor problem

I'm sorry for asking again so soon, but these transistors really give my head a spin.

1. The problem statement, all variables and given/known data

The problem is pretty much summed up by the following photograph:

3. The attempt at a solution

To be quite honest I'm really stumped here. I can go over what I know (Or at least what I think I know):

Since everything displayed here is in series, I'm presuming the current over each element is the same. The voltage over R1 should be 10 - v1, basically meaning if I could find v1 I should be able to find the current R1 and thus the current in every other element connected aswell, which would make the problem easy.

Vgs for the first transistor is 5 volts, and vgs=vds for the second transistor. R1 and R2 should have the same voltage drop across them.

All in all, 15 volts dissipate over this circuits as vdd = 10 volts and vss = -5.

After this, it completely stops. I've got the correct answer, which is

v1 = 6 v

and

v2 = 2 v

So by my logic, the current over the first resistance is (10-6)/1000 = 4 mA.

This is where I get confused, because if v2 = 2v, doesn't that mean the voltage drop across the first transistor is 4v aswell?

But if it is, this indicates that 16 mA runs through it, which isn't really possible if only 4 mA runs through the first resistance.

I tried checking what the voltage vds over the first transistor had to have been in order to allow for 4mA to pass through, and as far as I can remember the answer I got was sqrt(2)+1. Which is a fairly ugly number so I'm presuming this is wrong.

Anyone got a hint that can push me in the correct direction? It would be greatly appreciated. I'm dying to understand these blasted transistors.

**Physics Forums - The Fusion of Science and Community**

# Another NMOS-transistor problem

Have something to add?

- Similar discussions for: Another NMOS-transistor problem

Loading...

**Physics Forums - The Fusion of Science and Community**