So i think i got this straight since my last question. let's see :)
So my area of integration is: y=4 ; y=x2 and y=(x-2)2
the function is |x-1|
i must integrate with respect to dx first.
The Attempt at a Solution
So i sketched the area (see attatchment graphs should be cross at x=1 sorry for my bad sketch xD) and found that the upper limit for dx is x2 (so y½) and the lower is (x-2)(so y½-2)2
then noticed that since the function is the absolute value of x-1 i can divide it up into 2 functions
-x+1 (for x<1) and x-1 (for x>1) and with that in mind in my sketch i drew the line x=1 so my integrals are:
∫y½-21(-x+1) dx (this integral is from y½-2 to 1)
and ∫1y½(x-1)dx (this integral is from 1 to y½)
and then integrate all this with respect to y from 0 to 4.
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