Another Simple Heat Loss Question

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To size a heater for heating water from ambient temperature to a desired temperature in one hour, the heat loss from the glass must be considered. Initially, there is no heat loss, but it increases linearly as the temperature rises. The total energy needed to heat the water without heat loss is represented as X watts, while the heat loss at the final temperature is Y watts. Simply sizing the heater to (Y + X) watts may result in faster heating than necessary due to the initial lack of heat loss. A more accurate sizing approach would involve calculating the varying heat loss throughout the heating process to optimize the heater's wattage.
TheH
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I'm trying to size (in watts) a heater to heat a glass of water from ambient (Ti) to a certain temperature (Tf) in a given time period (say, 1 hour).

The heat-loss from the glass at Ti is 0 watts.
The heat-loss from the glass at Tf is Y watts.
I'm assuming that the heat loss increases linearly between Ti and Tf (I hope this is reasonable).
The energy needed (assuming no heat-loss) to heat the water from Ti->Tf in 1 hour is X watts.

Naturally, I can size the heater to be (Y + X) watts. However, this will heat the water up faster than necessary because initially there will be no heat-loss from the glass.

Is there a clever way to more accurately size this heater?

Thanks for your time.
 
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Note that here it is possible for X to be much larger than Y (when I want to heat the water up rapidly) and Y to be much larger than X (when I want to heat the water up slowly).
 
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