1. The problem statement, all variables and given/known data Two 10* wedges of negligible weight are used to move and position the 400-lb block. Knowing that the coefficient of static friction is 0.25 at all surfaces of contact, determine the smallest force P that should be applied as shown to one of the wedges. 2. Relevant equations I broke the 400lb block with wedge touching it up from the wedge on the ground. I've got two FBD's I analyzed. Considering the 400lb block I summed forces in y to find Fn2. Then I considered the wedge to find P. 3. The attempt at a solution The attachment has my solution. P should be 313lb I got 273lb.