I'm not going to give you the solution- the point is for you to find the solution. I will suggest this: your line is given by the vector equation r= <5, 2, 10>+ t<0,-1,4> so <0, -1, 4> is a vector pointing in the direction of that line. Also, the plane -x+ 0y+ 2z= 10 has <-1, 0, 2> as normal vector (that is <-1, 0, 2> is perpendicular to the plane).
What must be true of those two vectors in order that the line and plane be perpendicular? parallel? Are those true?