Answer Right? Calculate Satellite Slow-down, Find Relativity Speed-up

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The discussion revolves around calculating the slow-down of a satellite at 27,000 km altitude and the effects of general relativity on its speed. The initial calculation using the equation for gravitational time dilation yields a result very close to 1, indicating minimal difference between satellite and ground clocks. Participants clarify that "slow down" and "speed up" likely refer to gravitational time dilation rather than tidal drag or orbital speeds. There is confusion regarding the expected behavior of the satellite clock compared to ground clocks, prompting a reevaluation of the calculations. The conversation emphasizes the importance of understanding the implications of general relativity in these scenarios.
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Homework Statement


calculate the slow down on a satellite at height 27,000 km
how find the amount of speed up due to general relativity

Homework Equations


sqrt(1-GM/R/c/c)

The Attempt at a Solution


ok sqrt(1-(6.67*10^-11)*(6*10^24)/(27000000)/(3*10^8)/(3*10^8))

Why do i get .9999999994? it makes sense right? The M is right right?
 
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What do you mean by "slow down" and "speed up" - you don't seem to be talking about tidal drag or orbital speeds here.

Do you mean the gravitational time dilation?
In which case you seem to have the wrong equation.

The number real close to 1 usually means that the satellite and ground clocks are very nearly in agreement. Would you expect this to happen? Or would you expect the satellite clock to be much slower (or much faster) than a ground-based clock?
 

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