Answer: Volume of 4π/3 x 6495kg/m³ x 0.026m³ in kg

[you_of_eh]

Express the answer with the correct units and to the correct number of significant digits:

4pi/3(6495 kg/m^3)(0.026m)^3

-I know that the units in the answer would be kg because the m^3's will cancel.
-It is the sig figs that are giving me trouble. (perhaps the "pi" is screwing me up)

Thanks

 

[symbolipoint]

The "4" and the "3" seem to be integers and have unlimited significant figures, thereby not limiting the figures in the result. The 0.026 seems to have the fewest, therefore, TWO significant figures. Adjust your answer to two significant figures (AFTER performing your computation, not before).