Any way to figure out what this finite geometric series sums to?

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SUMMARY

The finite geometric series summation formula for \(\sum_{k=0}^{n - 1} ar^{4k}\) can be derived using the standard formula for geometric series. Specifically, the formula \(\sum_{k=0}^{n - 1} ar^{k} = a\frac{1 - r^n}{1 - r}\) can be adapted by substituting \(r\) with \(r^4\). This results in the formula \(\sum_{k=0}^{n - 1} ar^{4k} = a\frac{1 - (r^4)^n}{1 - r^4}\). The discussion highlights the simplicity of this adaptation, as noted by user micromass.

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jdinatale
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I would like to find a nice formula for [itex]\sum_{k=0}^{n - 1}ar^{4k}[/itex]. I know that [itex]\sum_{k=0}^{n - 1}ar^{k} = a\frac{1 - r^n}{1 - r}[/itex] and was wondering if there was some sort of analogue.
 
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Use the formula with [itex]r^4[/itex] instead of r.
 
micromass said:
Use the formula with [itex]r^4[/itex] instead of r.

Thank you micromass for your help. Wow that was really simple.
 

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