Apparent power, impedance and alternating current.

AI Thread Summary
To find the total apparent power of two serially connected impedances with apparent powers S1 and S2 both equal to 200 VA, the complex powers must be summed. The first impedance has a phase angle of π/3, while the second has a phase angle of 0. The real power for the first impedance is calculated as P1 = cos(π/3) * 200 = 100 W, and for the second, P2 = cos(0) * 200 = 200 W. The total apparent power can be determined by summing the complex powers, represented in the complex plane, where the angle between S1 and S2 is the same as that of the impedances. The final answer will be the magnitude of the resultant vector from this summation.
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Homework Statement


Two serially connected impedances one with \Phi = π/3 and other with \Phi = 0. They have apparent power of S1=S2=200VA. Find total apparent power.



Homework Equations



S = sqrt(P^2 + Q^2)



The Attempt at a Solution



so cosPhi = P1/S1. So P1=cosπ/3*200=100W. For other one P2 = cos0*200=200W. How should I continue? Should I find Q too and derive somehow a equation to sum those powers?
 
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The complex power, S, delivered to the load is:
S = S1 + S2

and the angle between S1 and S2 is the same as the angle between the impedances.

You want to find the apparent power |S| = |S1 + S2|. If, say:
S1 = 200∠0
S2 = 200∠π/3

Try drawing them in the complex plane. The length of their sum is the answer you're after.
 
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