Apparent vs. actual speed for moving star

  • Thread starter Thread starter QuantumCurt
  • Start date Start date
  • Tags Tags
    Speed Star
AI Thread Summary
The discussion revolves around understanding the apparent speed of a star moving at an angle to the observer on Earth, emphasizing the distinction between apparent and actual speed. The apparent speed is calculated using the formula Δs/ΔT, where Δs is the distance the star moves across the celestial sphere and ΔT is the time difference for light signals to reach Earth. It is noted that the maximum apparent speed occurs when the angle θ is 90 degrees, leading to the conclusion that the apparent speed can exceed the speed of light (c) even if the actual speed (v) is less than c. Participants clarify that the problem does not lack information and is seeking a symbolic solution. The key takeaway is that the apparent speed can be significantly greater than the actual speed due to the effects of light travel time.
QuantumCurt
Education Advisor
Messages
726
Reaction score
166
This is for a classed called Special Relativity and Math Methods. This problem doesn't involve special relativity though, since it's all from the same frame of reference.

1. Homework Statement

Every 2 years, more or less, The New York Times publishes an article in which some astronomer claims to have found an object traveling faster than the speed of light. Many of these reports result from a failure to distinguish what is seen from what actually happens– that is, from a failure to account for light travel time. Here’s an example: A star is traveling with speed v at an angle θ to the line of sight from Earth. Astronomers on Earth observe the star thanks to the light it emits, which travels from the moving star to their telescopes. The figure below shows the situation, with the thick arrow denoting the path of the star, and the vertical thin arrows denoting the light rays seen by the astronomers.

(a) What is the star’s apparent speed across the sky? Let me clarify a bit: Let a and b be two positions along the star’s path. Suppose the light signal from point a reaches the Earth at time Ta while the signal from point b arrives at time Tb. LetΔT≡Tb–Ta be the difference between these arrival times. Further, let Δs be the distance the star traveled across the celestial sphere between points a and b, i.e., the distance it moved in the only direction the astronomers can perceive: perpendicular to their line of sight. The apparent speed of the star is Δs/ΔT→that’s what you need to calculate.​

(b) What angle θ gives the maximum apparent speed?

(c) Show explicitly that the apparent speed can be much greater than c, even if v itself is less than c. Hint: a quick way to accomplish this is by finding specific values of v and θ that give the result you seek.

Here's the included diagram:
phy225.PNG


The Attempt at a Solution



In my attempt I considered the path of the star to simply be ##v\Delta{T}##, giving it the same units as ##\Delta{S}##. The apparent speed of the star is ##\frac{\Delta{S}}{\Delta{T}}##

$$sin \theta=\frac{\Delta{S}}{v \Delta{T}}$$

So

$$\frac{\Delta{S}}{\Delta{T}}=v_{apparent}=v sin \theta$$

This seems valid to me, but it doesn't make sense in the context of the rest of the problem. Obviously for part b the maximum speed would be when ##sin \theta=1##, which is at 90 degrees. But part c states that this relationship can show an apparent speed much greater than c, which this equation does not show, given that v is less than c.

Any input would be very appreciated!
 
Physics news on Phys.org
The problem statement's missing a parallax distance/measurement somewhere. @marcus
 
I didn't really get the impression that it was missing any information. I think they're just looking for a symbolic solution here.
 
o:) Nothing missing.
QuantumCurt said:
v apparent =vsinθ
sinθ = 0 to 1; vapp/(0 to 1) = "v. "
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top