- #1
wrldt
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Let {xn}n = 1[itex]\infty[/itex] be a bounded sequence
and
{xnj} be a convergent subsequence, each one converging to L.
Want to show that {xn[}[/itex]n = 1[itex]\infty[/itex] converges to L.
My proof is as follows.
Suppose that {xn}n = 1[itex]\infty[/itex] does not converge to L; this implies that there is a subsequence |{xnj}-L|[itex]\geq[/itex][itex]\epsilon[/itex]. However by B-W there exists a subsequence of that subsequence that converges, and it must converge to L. However this is a contradiction.
Is this sufficient?
and
{xnj} be a convergent subsequence, each one converging to L.
Want to show that {xn[}[/itex]n = 1[itex]\infty[/itex] converges to L.
My proof is as follows.
Suppose that {xn}n = 1[itex]\infty[/itex] does not converge to L; this implies that there is a subsequence |{xnj}-L|[itex]\geq[/itex][itex]\epsilon[/itex]. However by B-W there exists a subsequence of that subsequence that converges, and it must converge to L. However this is a contradiction.
Is this sufficient?