- #1
lyranger
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Really need help for this one. Cheers!
Question: calculate function z/(1-cos z) integrated in ac ounterclockwise circular contour given by |z-2pi|= 1
Clearly the pole in the given contour is 2pi. But the problem is: if it's a simple pole, then apply formula
we have Residue=lim (z-2pi) * z/(1-cos z) where z->2pi. This limit does not exist.
So I reckon 2pi might be a higher order pole but this actually makes no sense and even if it's true,
there is a really nasty differentiation.
Any thoughts.?
Homework Statement
Question: calculate function z/(1-cos z) integrated in ac ounterclockwise circular contour given by |z-2pi|= 1
Homework Equations
The Attempt at a Solution
Clearly the pole in the given contour is 2pi. But the problem is: if it's a simple pole, then apply formula
we have Residue=lim (z-2pi) * z/(1-cos z) where z->2pi. This limit does not exist.
So I reckon 2pi might be a higher order pole but this actually makes no sense and even if it's true,
there is a really nasty differentiation.
Any thoughts.?
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