Application of Liouville's Theorem (Complex Analysis)

In summary, the problem is asking us to prove that if a meromorphic function f is bounded by |z|^6, then f must be identically zero. We can use Liouville's theorem to show that the quotient f(z)^5/z^6 is bounded by 1, but this alone is not enough to prove that f is constant. To prove this, we must also show that f is entire, which can be done by noting that f must have a zero at the origin and considering the form f(z) = z^ng(z). After simplifying, we can see that n must be greater than 1, implying that g(z) must also be identically zero.
  • #1
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Homework Statement


Prove that if [tex]f[/tex] is a meromorphic function [tex]f:\mathbb{C}\rightarrow\mathbb{C}[/tex] with

[tex]|f(z)|^5\leq |z|^6\quad\textrm{for all}\quad z\in\mathbb{C}[/tex]

Then [tex]f(z)=0[/tex] for all [tex]z\in\mathbb{C}[/tex]

Homework Equations


Liouville's Theorem

A bounded entire function is constant.

The Attempt at a Solution


I tried applying Liouville's theorem to the quotient [tex]f(z)^5/z^6[/tex] which is bounded by 1 but was unsuccessful in proving that f is constant.
 
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  • #2
Note that the hypothesis implies that [tex]f(z)^5/z^6[/tex] is a bounded function but because of the [tex]z^6[/tex] in the denominator, you must prove that it's also entire.

To prove this, note (again, by the hypothesis) that [tex]f(z)[/tex] must have a zero at the origin, so either [tex]f(z)[/tex] is identically zero, or [tex]f(z) = z^ng(z)[/tex]; but then

[tex]f(z)^5/z^6=z^{5n}g(z)^5/z^6[/tex]

And this implies that [tex] n > 1 [/tex]. After simplifying, what can you say about [tex]g(z)[/tex]?
 

Related to Application of Liouville's Theorem (Complex Analysis)

What is Liouville's Theorem?

Liouville's Theorem is a fundamental result in complex analysis that states any bounded entire function must be constant.

What are the applications of Liouville's Theorem?

Liouville's Theorem has many important applications in complex analysis, including the classification of entire functions, the proof of the fundamental theorem of algebra, and the proof of the Picard theorem.

How is Liouville's Theorem used in the proof of the fundamental theorem of algebra?

In the proof of the fundamental theorem of algebra, Liouville's Theorem is used to show that a non-constant polynomial must have at least one root. This is because if the polynomial were to have no roots, it would be an entire function with no zeros and therefore must be constant, which contradicts Liouville's Theorem.

What is the connection between Liouville's Theorem and the Picard theorem?

The Picard theorem is a generalization of Liouville's Theorem, which states that a non-constant entire function must take on all complex values, with at most one exception, infinitely often. This result is useful in many areas of complex analysis, including the study of meromorphic functions and the existence of solutions to certain differential equations.

Can Liouville's Theorem be extended to other types of functions?

Yes, there are extensions of Liouville's Theorem to other types of functions, such as meromorphic functions and analytic functions with certain growth conditions. These extensions are important in the study of complex analysis and have many applications.

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