Applying Gauss's Lemma to Calculate Legendre Symbol (6/13)

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Use Gauss Lemma (Number theory) to calculate the Legendre Symbol (\frac{6}{13}).

I know how to use Gauss Lemma. However we use the book: Ireland and Rosen. They define Gauss Lemma as:

(\frac{a}{p})=(-1)^n. They say: Let \pm m_t be the least residue of ta, where m_t is positive. As t ranges between 1 and \frac{(p-1)}{2}, n is the number of minus signs that occur in this way. I don't understand how to use this form of Gauss's Lemma
 
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What are a and p in this case? What does that make \frac{(p-1)}{2} ? What does that make the least residue of ta in this case?
 
Could you be more specific, I really do not know how to use this version of Gauss's Lemma. Could you show me some steps on how to start it this way?
 
You want to use the lemma for \left( \frac{6}{13} \right), which means you want an "a" and "p" such that \left( \frac{a}{p} \right) = \left( \frac{6}{13} \right) where "p" is a prime...surely you can think of at least one "a" and one "p" for which this will hold true?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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