Applying linearity in a circuit

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SUMMARY

The discussion focuses on applying linearity in circuit analysis to find the current Io, initially assumed to be 1 mA. The user calculated various voltages and currents, including VR1=9V, VR2=61V, and VR3=70V, but struggled with finding I3. The solution involved recognizing that rounding errors affected the calculations, with the correct value for I3 determined to be 3.05 mA, which fell within the acceptable tolerance for the online homework assignment.

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Homework Statement


Find Io in the network in the figure below using linearity and the assumption that Io = 1 mA.
Figure:http://i.imgur.com/Xtu0VmG.jpg

Homework Equations


KCL, KVL, basic analysis techniques.

The Attempt at a Solution


The following values I have calculated correctly:
VR1=9V
VR2=61V
VR3=70V
I1=1mA
I2=2mA
VR4=138V
VS=208v
I3=??
IS=??
IoActual=??

So, my trouble lies in finding I3, as once I find I3, I can easily find IS using KCL, though, the current source is doing something to the voltage drop across I3 that I'm not understanding.

How I tried to solve for I3 was the same way I solved for VS. Since the voltage drop across the source is 208v, then I assumed that the voltage drop across the two resistors on the left summed to 208v as well.

So, using Ohms Law: V/R=I, 208v/(42000Ω+26000Ω)=3mA, which is incorrect. Where did I go wrong?

Thank you
 
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Rounding errors probably. Your analysis is fine. Just use fractions instead of calculating decimals and rounding.
 
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vela said:
Rounding errors probably. Your analysis is fine. Just use fractions instead of calculating decimals and rounding.

Thank you very much Vela. You were correct. 3mA was incorrect, but 3.05mA was correct. (My online homework has a +/- 2% tolerance, so 0.5 was enough to fall outside of the threshold!

Thanks for verifying my methodology.
 

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