Applyings Newton 2nd Law and Kinematics

In summary, the rocket, with a mass of 10,000 kg, experiences an upward thrust of 118,000N. Using the equations a = ΣForce/mass and d=1/2at2+vit, the rocket's acceleration is calculated to be 11.8 m/s^2. Furthermore, to determine the net force acting on the rocket, you must consider the forces of gravity and the upward thrust. The net force is found to be 18,000N. The rocket will have moved 360 meters after 20 seconds and its velocity will be 18 m/s.
  • #1
jtwitty
35
0

Homework Statement



A 10,000 kg rocket is acted upon by a upward thrust of 118,000N

How fast will the rocket be moving after 20 seconds? How far will it have moved in this time?

Also, how do i determine the net force

Homework Equations



a = [tex]\Sigma[/tex]F/m

d=1/2at2+vit

The Attempt at a Solution



a = [tex]\Sigma[/tex]Force/mass

a = 118,000/10,000

a = 11.8?

------

to find how far

d=1/2at2+vit

d=1/2(11.9)(202)
d=2360
 
Last edited:
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  • #2
jtwitty said:
Also, how do i determine the net force
What forces act on the rocket? (Hint: There are two.)

Finding the net force is the first step before you can calculate the acceleration.
 
  • #3
Doc Al said:
What forces act on the rocket? (Hint: There are two.)

Finding the net force is the first step before you can calculate the acceleration.
gravity and the mass of the object?
 
  • #4
jtwitty said:
gravity and the mass of the object?
The force of gravity is one force. You're given the other. (Mass is not a force.)
 
  • #5
Doc Al said:
The force of gravity is one force. You're given the other. (Mass is not a force.)

oh you the upward thrust.

so its 118,000N is one force and 100,000N is the force of the Earth due to the mass of the object multiplied by 10 (in class we always round gravity to ten)
 
  • #6
Sounds good. So what's the net force?
 
  • #7
doc al said:
sounds good. So what's the net force?

1.18n??

edit: wait no, that's the accelaration. the net force is 18? idk :(
 
  • #8
jtwitty said:
1.18n??

edit: wait no, that's the accelaration. the net force is 18? idk :(
Careful--You're missing a factor of a thousand!
 
  • #9
Doc Al said:
Careful--You're missing a factor of a thousand!

idk what to do? :'(
 
  • #10
Try this: If you had 20 million dollars and you spent 10 million, how much would you have left? 10 dollars?
 
  • #11
Doc Al said:
Try this: If you had 20 million dollars and you spent 10 million, how much would you have left? 10 dollars?

10 million.

so would i have 18,000 as my netforce?
but don't i divide, not subtract?
 
  • #12
jtwitty said:
so would i have 18,000 as my netforce?
Exactly.
but don't i divide, not subtract?
Not to find the net force. But yes to find the acceleration. That's the next step.
 
  • #13
Thanks :)

ok so my acceleration would be 11.8 right?
 
Last edited:
  • #14
sorry i wrote it wrong, i mean 11.8
 
  • #15
jtwitty said:
sorry i wrote it wrong, i mean 11.8
How did you get 11.8?
 
  • #16
Doc Al said:
How did you get 11.8?

a=[tex]\Sigma[/tex]f/m

a=

---- ok mid post i just realized i used the wrong number!

a=18,000/10,000

a=1.8??
 
  • #17
jtwitty said:
a=[tex]\Sigma[/tex]f/m

a=

---- ok mid post i just realized i used the wrong number!

a=18,000/10,000

a=1.8??
Now you've got it.
 
  • #18
yay

ok so i am using the d=1/2at2 formula

d=1/2(1.8)(202)
D=360?
 
  • #19
jtwitty said:
yay

ok so i am using the d=1/2at2 formula

d=1/2(1.8)(202)
D=360?
Good! (What about the speed?)
 
  • #20
d=vi/t?

360=vi/20

vi=7200?

(vi = initial velocity)
 
  • #21
jtwitty said:
d=vi/t?

360=vi/20

vi=7200?

(vi = initial velocity)
No. Instead, consider the definition of acceleration.
 
  • #22
wait is this rght

v = d/t

v = 360/20

v = 18!
 
  • #23
jtwitty said:
wait is this rght

v = d/t

v = 360/20

v = 18!
That would give you the average velocity as the rocket rises, not its velocity after 20 seconds.
 
  • #24
Doc Al said:
That would give you the average velocity as the rocket rises, not its velocity after 20 seconds.

it's accelerating isn't it?

a = vf -vi / t

1.8 = vf -0 / 20

1.8 = vf /20

36 = vf?

i think that's it :)
 
  • #25
Good!
 
  • #26
thank you so much doc al you're my hero :)
 

1. What is Newton's 2nd Law of Motion?

Newton's 2nd Law of Motion states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. This means that the larger the force applied to an object, the greater its acceleration will be. And conversely, the more massive an object is, the less it will accelerate for the same amount of force applied.

2. How do you apply Newton's 2nd Law to solve problems?

To apply Newton's 2nd Law, you must first identify all the forces acting on the object and their directions. Then, you can use the formula F=ma, where F is the net force, m is the mass of the object, and a is the acceleration. Plug in the known values and solve for the unknown quantity. It is important to make sure all units are consistent in your calculations.

3. What is the difference between mass and weight?

Mass is a measure of the amount of matter in an object, while weight is a measure of the force of gravity acting on an object. Mass is measured in kilograms (kg), while weight is measured in newtons (N). On Earth, the weight of an object is directly proportional to its mass, but this may not be the case in other locations with different gravitational forces.

4. How does Newton's 2nd Law relate to kinematics?

Newton's 2nd Law is one of the fundamental principles used in kinematics, which is the study of motion. By applying this law, we can calculate the acceleration of an object and use it to determine its velocity and position over time. Kinematics also takes into account the initial velocity and displacement of an object, in addition to the acceleration from Newton's 2nd Law.

5. Can Newton's 2nd Law be applied to all types of motion?

Yes, Newton's 2nd Law is a universal law that can be applied to all types of motion, including linear, rotational, and projectile motion. As long as there is a net force acting on an object, its acceleration can be calculated and used to predict its motion. However, it should be noted that this law is most accurate for objects moving at speeds much slower than the speed of light.

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