Applyings Newton 2nd Law and Kinematics

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Homework Help Overview

The discussion revolves around a physics problem involving a rocket with a mass of 10,000 kg and an upward thrust of 118,000 N. Participants explore how to determine the rocket's acceleration, distance traveled after 20 seconds, and the net force acting on the rocket.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of net force, questioning the forces acting on the rocket, including thrust and gravity. There are attempts to clarify the relationship between mass, force, and acceleration, with some participants expressing confusion about the calculations.

Discussion Status

The discussion is active, with participants providing guidance on identifying forces and calculating net force. There is a mix of correct and incorrect reasoning as participants refine their understanding of the concepts involved.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an emphasis on understanding the definitions and relationships between force, mass, and acceleration.

jtwitty
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Homework Statement



A 10,000 kg rocket is acted upon by a upward thrust of 118,000N

How fast will the rocket be moving after 20 seconds? How far will it have moved in this time?

Also, how do i determine the net force

Homework Equations



a = [tex]\Sigma[/tex]F/m

d=1/2at2+vit

The Attempt at a Solution



a = [tex]\Sigma[/tex]Force/mass

a = 118,000/10,000

a = 11.8?

------

to find how far

d=1/2at2+vit

d=1/2(11.9)(202)
d=2360
 
Last edited:
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jtwitty said:
Also, how do i determine the net force
What forces act on the rocket? (Hint: There are two.)

Finding the net force is the first step before you can calculate the acceleration.
 
Doc Al said:
What forces act on the rocket? (Hint: There are two.)

Finding the net force is the first step before you can calculate the acceleration.
gravity and the mass of the object?
 
jtwitty said:
gravity and the mass of the object?
The force of gravity is one force. You're given the other. (Mass is not a force.)
 
Doc Al said:
The force of gravity is one force. You're given the other. (Mass is not a force.)

oh you the upward thrust.

so its 118,000N is one force and 100,000N is the force of the Earth due to the mass of the object multiplied by 10 (in class we always round gravity to ten)
 
Sounds good. So what's the net force?
 
doc al said:
sounds good. So what's the net force?

1.18n??

edit: wait no, that's the accelaration. the net force is 18? idk :(
 
jtwitty said:
1.18n??

edit: wait no, that's the accelaration. the net force is 18? idk :(
Careful--You're missing a factor of a thousand!
 
Doc Al said:
Careful--You're missing a factor of a thousand!

idk what to do? :'(
 
  • #10
Try this: If you had 20 million dollars and you spent 10 million, how much would you have left? 10 dollars?
 
  • #11
Doc Al said:
Try this: If you had 20 million dollars and you spent 10 million, how much would you have left? 10 dollars?

10 million.

so would i have 18,000 as my netforce?
but don't i divide, not subtract?
 
  • #12
jtwitty said:
so would i have 18,000 as my netforce?
Exactly.
but don't i divide, not subtract?
Not to find the net force. But yes to find the acceleration. That's the next step.
 
  • #13
Thanks :)

ok so my acceleration would be 11.8 right?
 
Last edited:
  • #14
sorry i wrote it wrong, i mean 11.8
 
  • #15
jtwitty said:
sorry i wrote it wrong, i mean 11.8
How did you get 11.8?
 
  • #16
Doc Al said:
How did you get 11.8?

a=[tex]\Sigma[/tex]f/m

a=

---- ok mid post i just realized i used the wrong number!

a=18,000/10,000

a=1.8??
 
  • #17
jtwitty said:
a=[tex]\Sigma[/tex]f/m

a=

---- ok mid post i just realized i used the wrong number!

a=18,000/10,000

a=1.8??
Now you've got it.
 
  • #18
yay

ok so i am using the d=1/2at2 formula

d=1/2(1.8)(202)
D=360?
 
  • #19
jtwitty said:
yay

ok so i am using the d=1/2at2 formula

d=1/2(1.8)(202)
D=360?
Good! (What about the speed?)
 
  • #20
d=vi/t?

360=vi/20

vi=7200?

(vi = initial velocity)
 
  • #21
jtwitty said:
d=vi/t?

360=vi/20

vi=7200?

(vi = initial velocity)
No. Instead, consider the definition of acceleration.
 
  • #22
wait is this rght

v = d/t

v = 360/20

v = 18!
 
  • #23
jtwitty said:
wait is this rght

v = d/t

v = 360/20

v = 18!
That would give you the average velocity as the rocket rises, not its velocity after 20 seconds.
 
  • #24
Doc Al said:
That would give you the average velocity as the rocket rises, not its velocity after 20 seconds.

it's accelerating isn't it?

a = vf -vi / t

1.8 = vf -0 / 20

1.8 = vf /20

36 = vf?

i think that's it :)
 
  • #25
Good!
 
  • #26
thank you so much doc al you're my hero :)
 

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