Arc of a cylinder - would appreciate help

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The discussion focuses on calculating the height of an arc extending from the base of a cylinder and determining the length of a segment across the base. The arc is 2.000 meters long and follows a 45-degree angle, with a cylinder base diameter of 4.990 meters. A straightforward formula using Pythagorean theorem is suggested, where height equals the base length divided by the square root of 2. The user expresses gratitude for the succinct explanation and shares that they independently arrived at the same conclusion. The conversation highlights the application of geometry in practical scenarios involving cylindrical shapes.
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Would really appreciate help with the following:
Firstly, could someone answer this (simple?) question for something I am trying to make?
Secondly, could you give me the most straightforward formula for working it out if I change the length?

Hope this makes sense.
I have a cylinder. I have an arc exactly 2.000m long extending up from the base of the cylinder at 45 degrees following the elliptical arc. The diameter of the base is 4.990m What is the height of the arc? What is the length of the segment across the base, or the length of the arc around the cylinder base perpendicular to the end of the arc.

Big Thanks
 
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If you "unroll" a cylinder you get a plane, so you can just use Pitagora's theorem:

height = base length = L/sqrt(2)
 
Petr Mugver said:
If you "unroll" a cylinder you get a plane, so you can just use Pitagora's theorem:

height = base length = L/sqrt(2)

Thanks,for putting it succinctly. I figured the same thing out in my bed last night.
 
In bed- that's where I do my best work!
 
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