Archimedean property of R proof

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Homework Statement


Using the density of Q(rationals) in R(real numbers), prove the Archimedean property.


Homework Equations


Density of Q in R: For all x,y in R, and x<y, there exists q in Q s/t x<q<y.
Archimedean property says: For every real number x there exists a natural number y such that y>x.


The Attempt at a Solution


So I know how to prove the density of Q in R using the Archimedean property but I'm not sure of how to do it the other way around. Also, I don't really understand why it makes sense to prove it the other way around? Any hints and explanations would be helpful! thanks
 
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The problem does seem that hard. If x is negative y can be 1. If x is positive you know that

x< q < x+1

where q is a positive rational

or
x< q = s/t

Remember what a rational number is ,that is, s and t are integers. You may also have to assume that s and t have no common factors eg we write 3/2 not -3/-2 :-).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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