- #36
DaveC426913
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I've struggled with this on and off over time.Dale said:It does, but the particle in question is the whole atom or molecule, not the electron. An excited atom is more massive than an atom in the ground state. In the transition the energy is lost to photons and/or KE.
(I know this is a digression, since now I'm invoking nuclear reactions, but humor me for a moment.)
When a nucleus f̶i̶s̶s̶e̶s̶ undergoes fission, and loses mass, that mass is carried away by a particle moving very fast. If I have read correctly, the momentum of that particle (which incorporates its KE) will account for the mass missing from the end product. True?
Does this mean that the energy that the mass was converted from is KE? No mysterious other energy emitted?If so, is the same momentum at work in a molecular reaction? i.e, is the change in the KE of the various particles factored into the equation?
(I'd better go back and read my books. This stuff is slipping out of my head. Actually ,maybe I'd better pick up some new books.)