Area and volume calculation (no integration))

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SUMMARY

The discussion focuses on calculating areas and volumes in different coordinate systems without using integration. The area of a rectangle is computed using the product ΔxΔy, while the area of a wedge in polar coordinates is derived from the formula area(wedge) = (area(circle(r+dr) - area(circle(r))) * (dtheta / 2*pi). For volume calculations, the volume of a parallelepiped is determined by ΔxΔyΔz, and the volume in spherical coordinates requires a more complex approach involving Δρ, Δφ, and Δθ. The discussion references the ancient Greeks' method of exhaustion as a precursor to calculus.

PREREQUISITES
  • Understanding of basic geometry concepts such as area and volume
  • Familiarity with polar and spherical coordinate systems
  • Knowledge of the method of exhaustion in historical mathematics
  • Basic understanding of calculus principles (though not required for this discussion)
NEXT STEPS
  • Research the method of exhaustion and its applications in geometry
  • Learn about polar coordinate area calculations and their derivations
  • Study volume calculations in spherical coordinates
  • Explore the historical development of calculus and its precursors
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Mathematicians, physics students, educators, and anyone interested in geometric calculations and historical mathematical methods.

Jhenrique
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I can compute the area of the rectangle formed by Δx and Δy simply by product ΔxΔy.
image.png


Now, how can I to compute the area in gray given Δr and Δθ?
image.png


Also, I can to compute the volume of a parallelepiped formed by Δx, Δy and Δz, simply multiplicand ΔxΔyΔz. But, how can I compute the volume in shpherical coordinates formed by Δρ, Δφ and Δθ?

Convention:
image.jpg
 
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If you know the radius then you can compute the wedge by computing the area of circles r and r+dr and an angle ratio dtheta/(2*pi) for dtheta measured in radians:

area(wedge) = area(circle(r+dr) - area(circle(r)) * (dtheta / 2*pi)

In spherical coordinates you have a more complicated situation where you could derive a formula for the 3D wedge using calculus.

If you're thinking the ancient greeks didn't know calculus so how did they algebraically arrive at the answer then
you need to read about their calculus precursor the method of exhaustion:

http://en.wikipedia.org/wiki/Method_of_exhaustion

http://www.math.ubc.ca/~cass/courses/m446-03/exhaustion.pdf

http://www-groups.dcs.st-and.ac.uk/history/HistTopics/The_rise_of_calculus.html
 

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