Area element, volume element and matrix

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SUMMARY

The discussion focuses on the mathematical formulation of area and volume elements using matrix representations in various coordinate systems. It highlights the surface parametrization \(\vec{x} = \vec{x}(u,v)\) and the corresponding surface-element normal vectors expressed as \(\mathrm{d}^2 \vec{F} = \frac{\partial \vec{x}}{\partial u} \times \frac{\partial \vec{x}}{\partial v} \mathrm{d} u \mathrm{d} v\). The volume element is derived from the triple product, yielding \(\mathrm{d}^3 \vec{x} = \mathrm{d} u \mathrm{d} v \mathrm{d} w \left (\frac{\partial \vec{x}}{\partial u} \times \frac{\partial \vec{x}}{\partial v} \right ) \cdot \frac{\partial \vec{x}}{\partial w}\). The discussion also clarifies that the area element is not simply represented as \(dx dy\) due to the geometric nature of the region being analyzed.

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  • Understanding of vector calculus and parametrization of surfaces
  • Familiarity with the concepts of Jacobian determinants
  • Knowledge of vector products and their geometric interpretations
  • Basic understanding of coordinate transformations
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Jhenrique
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I found this matrix in the wiki:

0d11bea7769792cf94e0be53c7b011a0.png


https://fr.wikipedia.org/wiki/Vites...luation_en_coordonn.C3.A9es_cart.C3.A9siennes

I think that it is very interesting because it express d²A not trivially as dxdy. So, I'd like of know if exist a matrix formulation for volume element and area element in others coordinate system...
 
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Suppose you have a surface parametrized as
[tex]\vec{x}=\vec{x}(u,v).[/tex]
Then the surface-element normal vectors are given by
[tex]\mathrm{d}^2 \vec{F}=\frac{\partial \vec{x}}{\partial u} \times \frac{\partial \vec{x}}{\partial v} \mathrm{d} u \mathrm{d} v.[/tex]
This is clear from the geometric meaning of the vector product as a (axial) vector with magnitude of the area of the parallelogram spanned by the two vectors and directed perpendicular to the surface with the orientation given by the right-hand rule.

In the same way, from the triple product giving the volume of a parallelipiped spanned by three vectors
[tex]\mathrm{d}^3 \vec{x}=\mathrm{d} u \mathrm{d} v \mathrm{d} w \left (\frac{\partial \vec{x}}{\partial u} \times \frac{\partial \vec{x}}{\partial v} \right ) \cdot \frac{\partial \vec{x}}{\partial w},[/tex]
where [itex](u,v,w)[/itex] are arbitrary "generalized coordinates". This is of course identical with the Jacobian determinant of the transformation law from generalized to Cartesian coordinates,
[tex]\mathrm{d}^3 \vec{x} =\mathrm{d} u \mathrm{d} v \mathrm{d} w \det \left (\frac{\partial(x,y,z)}{\partial(u,v,w)} \right ).[/tex]
 
Jhenrique said:
I found this matrix in the wiki:

0d11bea7769792cf94e0be53c7b011a0.png
Actually, the formula shows a determinant.
Jhenrique said:
https://fr.wikipedia.org/wiki/Vites...luation_en_coordonn.C3.A9es_cart.C3.A9siennes

I think that it is very interesting because it express d²A not trivially as dxdy.
The formula gives dA, not d2A. The reason it is not shown as dxdy is that the area is for a region that is approximately a sector of a circle, rather than for a rectangular area element. In the drawing in the wiki article, the coordinates of point M' are (x + dx, y + dy) and the coordinates of M are (x, y). If you connect point M with a segment perpendicular to OM', you get something that is nearly a right triangle. The area of this triangle would be approximately (1/2)dx dy, so it's clear that the area of the sector can't be dx dy.
Jhenrique said:
So, I'd like of know if exist a matrix formulation for volume element and area element in others coordinate system...
 

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