I'm trying to plot the graph r = sin 3t and find its area.(adsbygoogle = window.adsbygoogle || []).push({});

This is how far I've gotten:

The graph looks like a plane propellor with one propellor pointing downward, and two pointing up-left / up-right, with the length of each equal to 1. Now to get the area...

I have to figure out where the graph reaches 0... which I'm not sure how to do (I solve sin3t = 0 and get t = 0, pi, 2pi ?? )...

or...

I can just get the area from 0 to 2pi... so i'll try that:

A = intergral of (1/2 (sin 3t)^2 dt) from 0 to 2pi

the solution is:

1/2( t/2 - 1/12 sin(6t) )

If I plug in 0 or 2pi into this and solve, the last term becomes 0 and I get a weird answer... what do I do?!?

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# Homework Help: Area of a graph with polar coordinates

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