1. The problem statement, all variables and given/known data Find the volume of the solid given the following: y=x^2 y=0 x=1 x=2 revolved about x=4 2. Relevant equations Shell method: 2pi(x)([f(x)] dx 3. The attempt at a solution I shifted the function left 4 units, so I replaced x's with x+4 This makes the new functions: y=(x+4)^2 y=0 x=-3 x=-2 Using -2 and -3 as the bounds, I have the integral of 2(pi)x (x+4)^2 dx, which is to say 2(pi)x (x^2 + 8x + 16)dx, which equals 2(pi)(x^3 + 8x^2 + 16x) Integrating I get: 2(pi) [(x^4)/4 + (8x^3/3) + (16x^2/2)] After evaluating it from -3 to -2, I get a negative value. However, the right answer is supposed to be 67(pi)/6 Anyone think they can catch what's wrong?