- #1
uradnky
- 30
- 0
Homework Statement
Find the area bound by y= x - 2[tex]\sqrt{x}[/tex] and y=0
The Attempt at a Solution
X intercept = 4
Y intercept = 0
Using verticle rectangles..
dA = ((Upper curve)-(Lower curve)) dx
[tex]\int[/tex](dA = [tex]\int[/tex](0-(x-2[tex]\sqrt{x}[/tex])) dx
A= -(1/2X^2)-((2x^(3/2))/(2/3)) Evaluated from 0 to 4
A= 16
I understand this is an extremely easy question but I just cannot see where I have gone wrong with it. Is there a problem with my signs since the area I am finding is below the x-axis? Sorry if this is a bit messy, any help is appecricated, thanks.