So my calculus professor last semester said that 1(adsbygoogle = window.adsbygoogle || []).push({}); ^{∞}is just 1 if 1 is exactly 1. He said that 1^{∞}is an indeterminant form because the rate of change of x as x approaches 1 competes with the rate of change of ∞ as it gets larger in x^{∞}. He also said that 0/0 is an indeterminant form because the rate of change of x as x approaches 0 competes with the rate of change of y as y approaches 0 in x/y.

I'm confused now. So does that mean 1^{∞}is exactly 1 if we mean 1 is just 1?

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# Aren't indeterminant forms misleading?

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