Atmospheric Pressure: Why is it Equal?

AI Thread Summary
Atmospheric pressure is equal in all directions at a fixed location, meaning that regardless of surface orientation, the pressure value remains constant. The initial assertion that pressure at the bottom of a gas volume is defined by weight times height is incorrect, as this does not yield the proper units for pressure. Instead, pressure should be calculated using density times height, which aligns with the correct physical principles. The discussion highlights the importance of understanding the relationship between pressure and its units, emphasizing that clarity in terminology is crucial. Overall, the conversation centers on the fundamental concepts of pressure and its uniformity in a given space.
huyhohoang
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Hello everyone!
As we've known, the pressure at the bottom of a volume of gas is define by its weight times the height. So I wonder why the atmospheric pressure is equal in all direction?
Many thanks
 
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huyhohoang said:
Hello everyone!
As we've known, the pressure at the bottom of a volume of gas is define by its weight times the height. So I wonder why the atmospheric pressure is equal in all direction?
Many thanks
Hi.
I don't understand what makes you think one thing has something to do with the other.
 
When we say that the "pressure is equal in all directions," what we mean is that, at a given fixed location, no matter which way you orient a surface upon which the pressure is acting, you get the same value for the pressure. So, we are not referring to changes in pressure with spatial location.
 
huyhohoang said:
Hello everyone!
As we've known, the pressure at the bottom of a volume of gas is define by its weight times the height.
This is not true. Weight times height doesn't even have the right units to be a pressure.
 
nasu said:
This is not true. Weight times height doesn't even have the right units to be a pressure.
I think the statement about it being "the bottom of a volume" implies the OP correctly understands it's over the surface area at the bottom of the column.
 
russ_watters said:
I think the statement about it being "the bottom of a volume" implies the OP correctly understands it's over the surface area at the bottom of the column.
But the result would still be wrong. Weight times height does not have units of force.
Density times height -- now that would have units of pressure -- at least if you measured density in force units.
 
jbriggs444 said:
But the result would still be wrong. Weight times height does not have units of force.
Density times height -- now that would have units of pressure -- at least if you measured density in force units.
Yeah - he shouldn't have said height at all since he already has the weight. Still is only tangential to the question he's asking, so probably not worth the extra few posts discussing it.
 
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