Drakkith said:
Bob I don't see how that relates to the nuke vs high speed kinetic impact question. Perhaps I misunderstood one of your posts?
Drakkith
The basic question is how a 1MT nuclear device with blast energy but without any kinetic energy could deflect or slow down asteroid 99942 Apophis. The secret is
a) A nuclear device placed on the surface of the asteroid,
without drilling, can create a significant crater. For this you need to read chapter 6 of Glasstone's book The Effects of Nuclear Weapons (which gave you the link to in my prior post), and in particular review the plots of the crater size vs. depth of blast on pages 255 and 256. For
zero depth of a 1 MT device, the crater is over 300 feet deep. So a lot of mass is ejected.
b) The laws of physics (Newton's laws) require that both energy and momentum are conserved.
OK, now for the details. Assume that the mass of the asteroid is M = 8.6 x 10
7 tonnes (metric tons), and it has a velocity of 24,000 meters per second. Suppose the ejected mass from the crater is m
1=3.7 x 10
4 tonnes. So the remaining mass of the asteroid is M-m
1. Further, assume 10% of 1 MT, or 4.7 x 10
14 joules, is converted to kinetic energy of the two masses (E
1+E
2 = E
total).
Suppose the device is placed on the front of the astrroid, so the ejected mass is accelerated, and the remaining mass of the asteroid is decellerated.
Assignment: You have two equations in two unknowns (v
1 and v
2).
½m
1v
12 + ½(M-m
1)v
22 = 4.7 x 10
14 joules
m
1v
1 = -(M-m
1)v
2
How much is the asteroid slowed down? Suppose a 10 MT device were used instead?
Bob S