Average acceleration using vectors

AI Thread Summary
The discussion focuses on calculating the average acceleration of a bicyclist over a 14-second interval using vector representation. The initial and final velocities are given in different directions, complicating direct subtraction. Participants emphasize the need to express velocities as vectors, using i and j notation for east-west and north-south components, respectively. The correct approach involves calculating average acceleration separately for each direction and then determining the net acceleration magnitude. The misunderstanding stems from not accounting for the vector nature of velocity and acceleration in the calculations.
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At one instant a bicyclist is 30 m due east of a park's flagpole, going due south with a speed of 18 m/s. Then, 14 s later, the cyclist is 45 m due north of the flagpole, going due east with a speed of 9 m/s. For the cyclist in this 14 s interval, find each of the following.
A)average acceleration

What i did was, i used the fact that a=v/t. So i pluged in a=(9+(-18))/14. The acceleration I got was 1.93. that is the wrong answer. Can someone please tell what i did wrong and help me figure out a way to get the angle. thank You
 
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jperk980 said:
At one instant a bicyclist is 30 m due east of a park's flagpole, going due south with a speed of 18 m/s. Then, 14 s later, the cyclist is 45 m due north of the flagpole, going due east with a speed of 9 m/s. For the cyclist in this 14 s interval, find each of the following.
A)average acceleration

What i did was, i used the fact that a=v/t. So i pluged in a=(9+(-18))/14. The acceleration I got was 1.93. that is the wrong answer. Can someone please tell what i did wrong and help me figure out a way to get the angle. thank You

velocity and acceleration are vectors... can you write the two velocities in vector form... (use i and j vectors). Then calculate average acceleration just as you did, but you'll be subtracting two vectors...
 
sorry i missed type what i did i did subtract i did a=9-(-18)/14 and i got 1.93. i know the answer is 1.37 but i don't know how to get it
 
jperk980 said:
sorry i missed type what i did i did subtract i did a=9-(-18)/14 and i got 1.93. i know the answer is 1.37 but i don't know how to get it

You can't subtract like that because east and south aren't along the same line... write the two velocities as vectors (using i for east west... j for north south).

For example: 20m/s west is

\vec{v} = -20\vec{i}

20m/s north is:
\vec{v} = 20\vec{j}

Does this make sense?

If the notation doesn't make sense... then try it like this... what is the average acceleration in the east west direction (taking east as positive) ?

what is the average acceleration in the north south direction (taking north as positive) ?

What is the magnitude of the net acceleration?
 
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