Average Induced EMF in Loop of Wire Rotated in B-Field

AI Thread Summary
The discussion centers on calculating the average induced electromotive force (emf) in a wire loop rotated in a magnetic field. A 7.2 cm diameter loop is initially perpendicular to a 1.3 T magnetic field and is rotated to a parallel orientation in 0.20 seconds. The initial calculations yield an induced emf of 2.6E-2 V, but there is uncertainty regarding the area calculation and the need for trigonometric functions due to the rotation. Participants suggest considering the change in the dot product of vectors and mention the possibility of using the root mean square voltage by adjusting the formula. The conversation highlights the importance of accurately applying formulas in electromagnetic induction scenarios.
airkapp
Messages
58
Reaction score
0
A 7.2 cm diameter loop of wire is initially oriented perpendicular to a 1.3 T magnetic field. It is rotated so that its plane is parallel to the field direction in .20 s. What is the average induced emf in the loop?

A = πr2

A = π*.001 = .004 m

ФB = BA

= (1.3T)(.004m) = 5.2E-3 Wb

ФB / t = 0-5.2E-3 Wb / .20 s

= -2.6E-2 Wb/s

€ = -(1)( -2.6E-2 Wb/s)

= 2.6E-2 V


I think i messed up in my area of my formula. can someone help me out here.
 
Physics news on Phys.org
I don't see any trig functions there... because the loop is rotated, there has to be a change in the dot product of the vectors.

Remember that A . B = |A| |B| cos theta
 
Now that I think about it - can't you just take BA/t and then times it by 1/root(2) to get the root mean square voltage.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top