Average intensity problem? related to EM waves?

Click For Summary
SUMMARY

The discussion centers on calculating the average intensity and maximum electric field of a helium-neon laser beam with an average power of 0.85 mW at a distance of 1.0 m. The average intensity is determined using the formula I = Power / Area, where the area is calculated as π times (1.1 mm / 2)². The maximum electric field is derived from the intensity using the equation I = 0.5 εo c E², emphasizing the significance of the distance in determining intensity variations.

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with intensity calculations in physics
  • Knowledge of the permittivity of free space (εo)
  • Basic skills in using mathematical formulas for area and power
NEXT STEPS
  • Research the derivation of the intensity formula for electromagnetic waves
  • Learn about the significance of beam diameter in laser applications
  • Explore the relationship between intensity and electric field strength in EM waves
  • Study the properties of helium-neon lasers and their applications in laboratory settings
USEFUL FOR

Physics students, laser technicians, and anyone involved in optical engineering or electromagnetic theory will benefit from this discussion.

waterbottle12
Messages
4
Reaction score
0

Homework Statement


The helium-neon lasers that we use in lab produce light waves with an average power
of 0.85 mW. Suppose that at a distance of 1.0 m from the laser the beam has a diameter
of 1.1 mm. a) What is the average intensity of the laser beam 1.0 m from the laser? b)
What is the maximum electric field 1.0 m from the laser?

Homework Equations



I = Energy/ (area x time)

I= 0.5 (circly E with subscript o) x c x E^2

The Attempt at a Solution


a. I think its just power divided by area with area being pi times (1.1mm/2)^2
because Power is just energy over time. just double checking
b. when I say circly E thing I mean permitivity of free space (I'm sure that's spelled wrong)
and I just plug into solve for E right?...but than why did the question give "distance of 1.0 m from the laser"...is it just like superfluous info?
 
Physics news on Phys.org
Welcome to Physics Forums!

waterbottle12 said:

The Attempt at a Solution


a. I think its just power divided by area with area being pi times (1.1mm/2)^2
because Power is just energy over time. just double checking
b. when I say circly E thing I mean permitivity of free space (I'm sure that's spelled wrong)
and I just plug into solve for E right?...but than why did the question give "distance of 1.0 m from the laser"...is it just like superfluous info?

Yes, you are entirely correct for both parts.

For (b), they tell you it's at 1.0 m from the laser because you know what the intensity is at that distance. At other distances, the intensity can be something else (because the beam diameter can be different) and therefore you can't figure out what E is.

p.s. To type εo you can copy-and-paste this: [noparse]εo[/noparse]
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
2
Views
2K