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Average Rate of Change/Differentiation Problem

  1. Oct 3, 2011 #1
    If the average rate of change of a function f over the interval from x = 2 to x= 2 + h is given by 7e^h -4cos(2h), then f ' (2) = ?

    This is what I got:
    [f(2 + h) - f(h)]/h = 7e^h -4cos(2h)
    I know we are supposed to used Mean-Value Theorem, I just don't get how to do it.
  2. jcsd
  3. Oct 3, 2011 #2


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    Are you sure you don't mean [f(2 + h) - f(2)]/h? Take the limit of both sides as h->0.
    Last edited: Oct 3, 2011
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