# Average Rate of Change/Differentiation Problem

1. Oct 3, 2011

### lmiller14

If the average rate of change of a function f over the interval from x = 2 to x= 2 + h is given by 7e^h -4cos(2h), then f ' (2) = ?

This is what I got:
[f(2 + h) - f(h)]/h = 7e^h -4cos(2h)
I know we are supposed to used Mean-Value Theorem, I just don't get how to do it.

2. Oct 3, 2011

### Dick

Are you sure you don't mean [f(2 + h) - f(2)]/h? Take the limit of both sides as h->0.

Last edited: Oct 3, 2011