Average Rate of Change/Differentiation Problem

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SUMMARY

The average rate of change of the function f over the interval from x = 2 to x = 2 + h is expressed as 7e^h - 4cos(2h). To find f'(2), the Mean Value Theorem is applied, requiring the correct formulation of the difference quotient as [f(2 + h) - f(2)]/h. By taking the limit as h approaches 0, the derivative f'(2) can be determined accurately.

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If the average rate of change of a function f over the interval from x = 2 to x= 2 + h is given by 7e^h -4cos(2h), then f ' (2) = ?

This is what I got:
[f(2 + h) - f(h)]/h = 7e^h -4cos(2h)
I know we are supposed to used Mean-Value Theorem, I just don't get how to do it.
 
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Are you sure you don't mean [f(2 + h) - f(2)]/h? Take the limit of both sides as h->0.
 
Last edited:

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