Average relative velocity in calculating mean free path

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SUMMARY

The discussion focuses on the use of root mean square (RMS) relative velocity in calculating the mean free path, particularly in the context of molecular collisions. Participants clarify that using mean-relative-speed instead of RMS would yield a result of zero due to the vector nature of velocity. The conversation emphasizes the importance of adjusting derivations when substituting mean-relative-speed for RMS speed, particularly in applications like Brownian motion.

PREREQUISITES
  • Understanding of mean free path in kinetic theory
  • Familiarity with root mean square (RMS) calculations
  • Knowledge of molecular collisions and their implications
  • Basic concepts of vector velocities and their mathematical treatment
NEXT STEPS
  • Explore the derivation of mean free path using RMS relative velocity
  • Investigate the mathematical implications of using mean-relative-speed in kinetic theory
  • Study the applications of mean free path in Brownian motion
  • Learn about the differences between vector velocities and scalar speeds in physics
USEFUL FOR

Physics students, researchers in kinetic theory, and anyone studying molecular dynamics will benefit from this discussion.

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Try it and see what happens when you use the mean-relative-velocity. ;)
 
Thanks Simon,

I'm not really following. The mean-relative-velocity would be 0 since velocity is a vector. I think I meant to say mean-relative-speed. I would expect the mean-relative-speed to be less than the rms-relative-speed but that's about it.

Thanks
 
Ri-ight - so, look through your notes about mean free path, where it is applied (say: brownian motion) and use your idea of the mean-speed instead of the rms speed. (You'll have to adjust the derivation to account for the difference.) See what you get.

I could go and just describe in words why the rms speed is preferred etc etc ... but that's a lot of typing when I can just make you do the math. You asked the question: are you prepared to find the answer?
 

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