Dividing Polynomials: Solving Average Speed Questions in x+60 Miles Per Hour

AI Thread Summary
To determine the time taken for a trip where a car travels a distance of x^3 + 60x^2 + x + 60 miles at an average speed of x + 60 miles per hour, the formula t = d/v can be applied. The distance should be divided by the speed, leading to the need to divide the polynomial x^3 + 60x^2 + x + 60 by x + 60. This division will yield the time taken for the trip. Confusion arises from the polynomial division process, which is essential for solving the problem. Understanding polynomial division is key to finding the correct solution.
acuraintegra9
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If a car travels at a distance of x^3+60x^2+x+60 miles at an average speed of x+60 miles per hour, how long does the trip take??




not sure how to solve this problem either, Its in the whole chapter of dividing polynomials, so I tried dividing .. it all just basically said that it was a root?? i guess confused what to do...
 
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Try reading http://www.purplemath.com/modules/polydiv2.htm"

It has a good explanation and an example.
 
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acuraintegra9 said:
If a car travels at a distance of x^3+60x^2+x+60 miles at an average speed of x+60 miles per hour, how long does the trip take??




not sure how to solve this problem either, Its in the whole chapter of dividing polynomials, so I tried dividing .. it all just basically said that it was a root?? i guess confused what to do...
Velocity is "distance divided by time": v= d/t so tv= d and t= d/v. Yes, you want to divide x^3+ 60x^2+ x+ 60 by x+ 60.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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