Average value of x-coord and y-coord in a semicircle. multivariable calculus.

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Homework Help Overview

The discussion revolves around calculating the average height above the x-axis for points within a specified region defined by the inequalities 0 <= x <= 1 and 0 <= y <= x^2, within the context of multivariable calculus.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of "height" in relation to the y-coordinate and the setup of a double integral to find the average value.

Discussion Status

There is an ongoing exploration of the definition of height in this context, with some participants offering guidance on setting up the integral while others seek clarification on the reasoning behind using the y-coordinate as height.

Contextual Notes

Participants are navigating the definitions and assumptions related to the average height and the integration process, with some uncertainty about the terminology used in the problem statement.

mahrap
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Calculate the average height above the x-axis of a point in the region 0 <= x <= 1 , 0 <= y <= x^2. I don't know what function to use to find the average height.
 
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mahrap said:
Calculate the average height above the x-axis of a point in the region 0 <= x <= 1 , 0 <= y <= x^2. I don't know what function to use to find the average height.

I expect height means y. So you want to integrate y over the region then divide by the area of the region. Set it up as a double integral of y.
 
Dick said:
I expect height means y. So you want to integrate y over the region then divide by the area of the region. Set it up as a double integral of y.

Why would the height be y though? That's what i don't understand
 
mahrap said:
Why would the height be y though? That's what i don't understand

y is the distance of a point (x,y) to the x-axis. They are just calling that 'height'.
 

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