Average Velocity of a particle

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SUMMARY

The average velocity of a particle moving along the x-axis, described by the function v(t) = e^t + te^t, is calculated over the interval from t=0 to t=3. The correct average velocity is determined to be 20.086 ft/sec. The error in the initial calculation arose from incorrectly applying the derivative formula instead of the average value formula for the function over the specified interval. The average value of a function f(x) on [a, b] is given by (1/(b - a)) ∫_a^b f(x) dx.

PREREQUISITES
  • Understanding of calculus concepts, specifically integration and average value of a function.
  • Familiarity with the exponential function and its derivatives.
  • Knowledge of the fundamental theorem of calculus.
  • Ability to perform definite integrals.
NEXT STEPS
  • Study the average value of a function in calculus, focusing on the formula (1/(b - a)) ∫_a^b f(x) dx.
  • Learn how to compute definite integrals for functions involving exponentials.
  • Review the application of the fundamental theorem of calculus in solving average velocity problems.
  • Practice problems involving average velocity calculations for various functions.
USEFUL FOR

Students studying calculus, particularly those focusing on motion and average velocity problems, as well as educators seeking to clarify concepts related to integration and average values.

lude1
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Homework Statement



The velocity, in ft/sec, of a particle moving along the x-axis is given by the function v(t) = e^t + te^t. What is the average velocity of the particle from time t=0 to time t=3?

Answer: 20.086

Homework Equations





The Attempt at a Solution



Average velocity means the derivative formula, [s(t + Δt) - s(t)] / (Δt)
In other words, I get

[v(3) - v(0)] / (3-0)
[e3 - 3e3] / 3
And I got 26.447​

However, the answer is 20.086.

What did I do wrong?
 
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lude1 said:

Homework Statement



The velocity, in ft/sec, of a particle moving along the x-axis is given by the function v(t) = e^t + te^t. What is the average velocity of the particle from time t=0 to time t=3?

Answer: 20.086

Homework Equations





The Attempt at a Solution



Average velocity means the derivative formula, [s(t + Δt) - s(t)] / (Δt)
In other words, I get

[v(3) - v(0)] / (3-0)
[e3 - 3e3] / 3
And I got 26.447​

However, the answer is 20.086.

What did I do wrong?
The average value of a function f(x) on an interval [a, b] is
[tex]\frac{1}{b - a} \int_a^b f(x) dx[/tex]
 

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