Average acceleration given velocity points?

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SUMMARY

The average acceleration of Rocket A over the time interval of t=[0,60] seconds can be calculated using the formula (v(60) - v(0)) / (60 - 0). Given the velocity points of 0 ft/sec at t=0 and 75 ft/sec at t=60, the average acceleration is (75 - 0) / (60 - 0) = 1.25 ft/sec². The initial approach of calculating multiple acceleration points and averaging them is unnecessary for this specific problem.

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syeh
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How do you find average acceleration given a table with points of velocity (ft/sec)?

t (sec): 0 15 30 45 60
v(t) (ft/sec):0 40 60 70 75

the question asks: Find the average acceleration of Rocket A over t=[0,60] seconds.


I used change in v(t)/change in time to find 4 points of acceleration (2.667, 1.333, .667, .333). I added those and divided by 4 to get 1.25. But I do not think that is how to solve the problem.
 
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syeh said:
How do you find average acceleration given a table with points of velocity (ft/sec)?

t (sec): 0 15 30 45 60
v(t) (ft/sec):0 40 60 70 75

the question asks: Find the average acceleration of Rocket A over t=[0,60] seconds.


I used change in v(t)/change in time to find 4 points of acceleration (2.667, 1.333, .667, .333). I added those and divided by 4 to get 1.25. But I do not think that is how to solve the problem.

You just find the quotient (v(60)-v(0))/(60-0). That's average acceleration.
 

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