Balancing Vinegar and Baking soda equation

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The chemical reaction between baking soda (NaHCO3) and vinegar (CH3COOH) produces sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (H2O). To balance the equation, adding water to the products side results in the balanced equation: NaHCO3 + CH3COOH → NaCH3COO + CO2 + H2O. The discussion highlights the importance of including all reaction products for proper balancing. The reaction also indicates that the formation of carbon dioxide can turn blue cobalt paper pink, confirming the presence of water. Balancing chemical equations is crucial for understanding the stoichiometry of reactions.
pippo90
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NaHCO3 + CH3COOH --> NaCH3COO + CO2

how would I balance this equation? it is backing soda and vinegar, and it forms sodium acetate, CO2 and a substance that turns blue cobalt paper pink? So there is a product missing on the right hand side, so what would that product me and how would i balance the final equation, thanks.
 
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I believe water is also a reaction product. Actually if you add a water molecule to the right hand side, the equation should balance itself.
 
awsome thanks
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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