Ball Bouncing on an Inclined Plane: Force and Velocity Analysis

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The discussion focuses on analyzing the forces and velocities involved when a ball is dropped from a height and strikes an inclined plane. The user seeks to determine the force exerted on the ball upon impact and its velocity after bouncing off the surface. Initial calculations include the velocity formula V=(2gh)^0.5 and momentum p=mV, leading to considerations of gravitational force and its components on the inclined plane. The user expresses uncertainty about the calculations and invites further questions for clarification. The thread emphasizes the importance of understanding the dynamics of motion and force interactions in this scenario.
SpicVir
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Hello, my problem:

A ball (assume its a point) is dropped from height h without initial speed, after some time of falling it will hit an inclined plane (at angle alpha to normal) and bounce off (see the pretty picture, i think it explains alot).

Question 1: What is the force F?
Question 2: What is the velocity after the bounce?

Started with:
V=(2gh)-1

Ek=(mV2)/2

p=mV => p=m(2gh)-1

F=ma

Q=mg (weight)

My brainstorming yielded this:
Qn=Qcos(alpha)
Fq=Fcos(alpha)

*what is marked as -Fn in the picture* = -(Fn+Qn)

I hope that is it, but I can be forgetful at times. So if you have questions... shoot!
 

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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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