Ball Bouncing on an Inclined Plane: Force and Velocity Analysis

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SUMMARY

The discussion focuses on analyzing the forces and velocities involved when a ball is dropped from height h and subsequently bounces off an inclined plane at angle alpha. The key equations derived include the initial velocity V as V = (2gh)^(1/2), kinetic energy Ek = (mV^2)/2, and momentum p = mV. The force F acting on the ball is defined using F = ma, with weight Q represented as Q = mg. The components of the forces acting on the ball during the bounce are also explored, specifically Qn = Qcos(alpha) and Fq = Fcos(alpha).

PREREQUISITES
  • Understanding of basic physics concepts such as force, velocity, and momentum.
  • Familiarity with equations of motion, particularly those related to gravitational acceleration.
  • Knowledge of trigonometry, specifically how to resolve forces into components using angles.
  • Ability to apply Newton's laws of motion in practical scenarios.
NEXT STEPS
  • Study the derivation of projectile motion equations in inclined planes.
  • Learn about energy conservation principles in elastic and inelastic collisions.
  • Explore advanced topics in dynamics, such as impulse and momentum transfer during collisions.
  • Investigate the effects of different angles of inclination on the bounce dynamics of objects.
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Physics students, educators, and anyone interested in mechanics, particularly those studying motion and forces in inclined planes.

SpicVir
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Hello, my problem:

A ball (assume its a point) is dropped from height h without initial speed, after some time of falling it will hit an inclined plane (at angle alpha to normal) and bounce off (see the pretty picture, i think it explains a lot).

Question 1: What is the force F?
Question 2: What is the velocity after the bounce?

Started with:
V=(2gh)-1

Ek=(mV2)/2

p=mV => p=m(2gh)-1

F=ma

Q=mg (weight)

My brainstorming yielded this:
Qn=Qcos(alpha)
Fq=Fcos(alpha)

*what is marked as -Fn in the picture* = -(Fn+Qn)

I hope that is it, but I can be forgetful at times. So if you have questions... shoot!
 

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