Ball hitting block, elastic collision

AI Thread Summary
A 0.500 kg ball attached to a 70 cm cord strikes a stationary 2.5 kg block in a perfectly elastic collision. The initial potential energy of the ball is calculated to be 3.43 J, leading to a kinetic energy of 2.62 J just before the impact. The equations used for the final velocities after the collision suggest V1f is -1.75 m/s and V2f is 0.87 m/s. However, there is confusion regarding the setup, specifically how the cord is attached and whether it behaves like a spring. Clarification on the diagram and cord attachment is needed for a complete understanding of the problem.
geauxKTM
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Homework Statement



.500kg ball attached to a cord that is 70 cm long. ball strikes a 2.5kg block at rest

what is the speed of the ball just before hitting the block
and collison is perfectly elastic find speed of ball and block after collision

Homework Equations





The Attempt at a Solution


Uo=MGY
(.5)(9.8)(.7)= 3.43J
Ko=0
Uf=0
J=.5(.5)v^2= 2.62

part b
2.62=V2f-V1f
1.31=.5V1f+2.5V2f

matrix on calc
V1f= -1.75
V2f=.87
 
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I don't understand the question. Do you have a diagram? How is the cord attached? Is it a spring or something?
 
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